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Math Help - max and min pre cal

  1. #1
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    Question max and min pre cal

    I can't seem to calculate the min of this problem.
    c=350,000-140x+0.030xsq
    Could you please walk me through the problem?
    thanks
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by Donnastar View Post
    I can't seem to calculate the min of this problem.
    c=350,000-140x+0.030xsq
    Could you please walk me through the problem?
    thanks
    c=.030x^2-140x+350000

    Find the x-coordinate of the vertex using x=\frac{-b}{2a}

    Now, find c\left(\frac{-b}{2a}\right)
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  3. #3
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    Question max and min

    I can't come up with the correct answer when I pulg the numbers into the formula. Could you make it real simple for me? thanks
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  4. #4
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    Quote Originally Posted by Donnastar View Post
    I can't come up with the correct answer when I pulg the numbers into the formula. Could you make it real simple for me? thanks
    c=ax^2+bx+c

    c=.030x^2-140x+350000

    a=.030

    b=-140

    c=350000

    Substituting,

    x=\frac{-b}{2a}=\frac{140}{.06}=\frac{7000}{3}

    c\left(\frac{7000}{3}\right)=.030\left(\frac{7000}  {3}\right)^2-140\left(\frac{7000}{3}\right)+350000

    c\left(\frac{7000}{3}\right)=\boxed{\frac{560000}{  3}}

    That should be your minimum.
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