Find the values of t for which the velocity of the car is parallel to the vector (i + j)

v = (3r^2 - 2t + 8)i + (5t + 6)j ms^-1

Its doing my head in not being able to work this out (Angry)

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- September 26th 2008, 09:09 AMCarl Felthamvectors
Find the values of t for which the velocity of the car is parallel to the vector (i + j)

v = (3r^2 - 2t + 8)i + (5t + 6)j ms^-1

Its doing my head in not being able to work this out (Angry) - September 26th 2008, 09:21 AMcivodul
For vectors to be parallel they need to have the same slope.

vector i+j has slope: 1/1= 1

so slope of v has to be 1 which is:

(5t+6)/(3t^2-2t+8)=1

So it is a second degree polynomial equation to solve.

civodul - September 26th 2008, 12:41 PMSoroban
Hello, Carl!

Quote:

Find the values of for which the velocity of the car

is parallel to the vector

. .

A vector parallel to has the form: .

. . That is, the coefficients are equal.

So we have: .

Factor: .

- September 26th 2008, 02:56 PMProve It