# points of intersection.

• Sep 26th 2008, 07:25 AM
Mathematix
points of intersection.
OK, so heres the question:

On the same axes draw the curves of equations y = 6 / x. ( As in the asymptotes ) and y = 1 + x.

^^ OK, so done that.. now next part :

The curves intersect at points A and B, find the co-ordinates of A and B.

So, I dont know what to do here. Don't you just make them equal to each other and solve ?

Can someone explain, step by step and a link would be helpful , with more examples and explanations as well please ?
• Sep 26th 2008, 07:30 AM
kalagota
Quote:

Originally Posted by Mathematix
OK, so heres the question:

On the same axes draw the curves of equations y = 6 / x. ( As in the asymptotes ) and y = 1 + x.

^^ OK, so done that.. now next part :

The curves intersect at points A and B, find the co-ordinates of A and B.

So, I dont know what to do here. Don't you just make them equal to each other and solve ?

Can someone explain, step by step and a link would be helpful , with more examples and explanations as well please ?

yes, equate them.. then solve for \$\displaystyle x\$'s.. finally substitute the \$\displaystyle x\$'s to any of the two curve to find their respective y-component.. then you'll get the coordinates..
• Sep 26th 2008, 08:23 AM
Mathematix
Thanks, but I still dont understand. (Headbang)

x = ( 6 / x ) - 1

Then what ...? How do I substitute that into y = x + 1 or x = y - 1 ??
• Sep 26th 2008, 03:18 PM
kalagota
Quote:

Originally Posted by Mathematix
Thanks, but I still dont understand. (Headbang)

x = ( 6 / x ) - 1

Then what ...? How do I substitute that into y = x + 1 or x = y - 1 ??

yup, you have x+1 = 6/x

then multiplying 6 to both sides, we have
\$\displaystyle x^2 + x = 6\$ or \$\displaystyle x^2 + x - 6 = 0\$

then factor...