- if you decide to make two squares. Let x the length of fencing used for the first square. The second square will be 200-x.
x/4 and (200-x)/4 will be the lengths of the sides of each square.
Thus their added area will be :
Note that and find the maximum of
Solve for t in , since when the ball hits the ground, its height is 0.2. If a ball is thrown upward from a building 30m tall and the ball has a vertical velocity of 25m/s, then its approximate height above the ground t seconds later is fiven by h(t)=30=25t-5t^2
a.) after how many seconds does the ball hit the ground?
Well, you can do itb.) what is the domain of h?
Find the maximumc.) How high does the ball go