# Math Help - Cost of Triangular Lot

1. ## Cost of Triangular Lot

The dimensions of a triangular lot are 100 feet by 50 feet by 75 feet. If the price of such land is $3 per square foot, how much does the lot cost? Does this question have anything to do with volume? 2. Originally Posted by magentarita The dimensions of a triangular lot are 100 feet by 50 feet by 75 feet. If the price of such land is$3 per square foot, how much does the lot cost?

Does this question have anything to do with volume?
Has nothing to do with volume.

Area of Triangle when the length of the three sides is known:

$A=\frac{1}{4}\sqrt{P(P-2a)(P-2b)(P-2c)}$

where P is total perimeter and a, b and c are the lengths of the three sides.

A similar formula is:

$A=\sqrt{P(P-a)(P-b)(P-c)}$

where P is half the perimeter, or $\frac{a+b+c}{2}$

Once you find the area, multiply it by $3 to get total cost of lot. 3. ## wonderful... Originally Posted by masters Has nothing to do with volume. Area of Triangle when the length of the three sides is known: $A=\frac{1}{4}\sqrt{P(P-2a)(P-2b)(P-2c)}$ where P is total perimeter and a, b and c are the lengths of the three sides. A similar formula is: $A=\sqrt{P(P-a)(P-b)(P-c)}$ where P is half the perimeter, or $\frac{a+b+c}{2}$ Once you find the area, multiply it by$3 to get total cost of lot.
Great reply with a chance for me to do some of the work.