solve the equation graphically in the given interval. state each answer correct to two decimals. 16x^3+16x^2=x+1 ; [-2,2]
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get out your graphing calculator ... graph the function y1 = 16x^3 + 16x^2 - x -1 calculate the x-intercepts (zeros) in the given interval.
Originally Posted by Heather10 solve the equation graphically in the given interval. state each answer correct to two decimals. 16x^3+16x^2=x+1 ; [-2,2] Now, draw the graph f(x) = 16x^3 + 16x^2 and f(x)= x+1 The solution graphically is (- 1, 0), (- 0.25, 0.75), (0.25, 1.25)
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