# Thread: inverse of this equation

1. ## inverse of this equation

what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.

2. Originally Posted by darcalman
what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
Where has the $\pm$ come from?? You're taking a cube root not a square root.

$x = (y + 4)^{\color{red}3} + 2 \Rightarrow x - 2 = (y + 4)^{\color{red}3} \Rightarrow \, ....$

3. Originally Posted by darcalman
what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
If you mean

$y = \sqrt[3]{x-2} - 4$

then the $\pm$-sign is wrong because the 3rd root is unambiguous.

Mr. F. you are too fast - or I lost my typing skills

4. so the answer is cubed root of x-2 then -4 is the answer. ok thanks i understand now.

5. ?? Reality Check ??

Do "equation"s have inverses?