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Math Help - inverse of this equation

  1. #1
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    inverse of this equation

    what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
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    Quote Originally Posted by darcalman View Post
    what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
    Where has the \pm come from?? You're taking a cube root not a square root.

    x = (y + 4)^{\color{red}3} + 2 \Rightarrow x - 2 = (y + 4)^{\color{red}3} \Rightarrow \, ....
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  3. #3
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    Quote Originally Posted by darcalman View Post
    what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
    If you mean

    y = \sqrt[3]{x-2} - 4

    then the \pm-sign is wrong because the 3rd root is unambiguous.


    Mr. F. you are too fast - or I lost my typing skills
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  4. #4
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    so the answer is cubed root of x-2 then -4 is the answer. ok thanks i understand now.
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  5. #5
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    ?? Reality Check ??

    Do "equation"s have inverses?
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