what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4.
Follow Math Help Forum on Facebook and Google+
Originally Posted by darcalman what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4. Where has the $\displaystyle \pm$ come from?? You're taking a cube root not a square root. $\displaystyle x = (y + 4)^{\color{red}3} + 2 \Rightarrow x - 2 = (y + 4)^{\color{red}3} \Rightarrow \, ....$
Originally Posted by darcalman what is the inverse of this equation y=(x+4)^3+2? please i put it as y=+3(square root of)x-2 then -4. If you mean $\displaystyle y = \sqrt[3]{x-2} - 4$ then the $\displaystyle \pm$-sign is wrong because the 3rd root is unambiguous. Mr. F. you are too fast - or I lost my typing skills
so the answer is cubed root of x-2 then -4 is the answer. ok thanks i understand now.
?? Reality Check ?? Do "equation"s have inverses?
View Tag Cloud