Results 1 to 3 of 3

- Sep 19th 2008, 08:24 PM #1
## Help me!

Given that the x-intercept of a line is twice the y-intercept of its y-intercept and that the line passes thru the intersection between the lines 3y+x=3 and 4y-3x=5, find the eqn of the line. i found the intersection of the line and use the point to find the gradient of the the two point at the x-intercept and x-intercept so that i can eqate them and find the intercept. however i got a large fraction and is very confusing. Did i do wrongly? or is there another method to solve this?

- Sep 19th 2008, 08:53 PM #2

- Sep 19th 2008, 09:06 PM #3

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 12,028
- Thanks
- 846

Hello, helloying!

Given that the x-intercept of a line is twice the y-intercept,

. . and that the line passes thru the intersection of the lines

find the equation of the line.

The lines intersect at: .

The line has y-intercept and x-intercept

The slope of line is: .

The line thorugh with slope has the equation:

. .