1. ## graphs

i posted this before but i wasn't sure where it went so its missing, please view attached files and respond.

2. For problem number 1, I'll give you a hint: the domain is all real numbers except one, and the range is all real numbers except one.

For problem number 2, you should recheck your answers. If you substitute $\displaystyle x_1$ into $\displaystyle f(x)$, what you will get is $\displaystyle f(x_1)$, which is a number, not an interval. For the interval questions, you are missing some intervals. Sometimes you will not be able to write the answer as a single interval, and you will have to write it as a union of intervals, for example: (0, 1) U (3, 4) consists of all numbers that are either between 0 and 1 or between 3 and 4. For the sake of your questions, the notation (0, 1); (3, 4) would probably also be appropriate.
Finally, there is an interval on which the graph is constant.

For problem number 3, the composition f(g(x)) is correct, however, you have computed that composition incorrectly. You are not multiplying the functions together, but you are taking the output from one function (g) and using it as input for the other function (f).

For problem number 4, I'll get you started. The data points are (4, 650) and (8, 400).

3. A.) (4y,650)=(2600,650) and (8y,400)=(3200,400)
these points are given in (x,y)

B.) slope=(y2-y1)/(x2-x1)
where i have two coordinates, (x1,y1) and (x2,y2). x1 is the x value furthest left on the graph, y1 is its cooresponding y value. In this case x1=2600, so y1=650.

i got m= -5/12 am i right?

c) y=mx+b where m= slope
plug in slope and an (x,y) value i have been given then solve for b.
then for my answer y=(value calculated in questionb)*x+(value calculated at start of question c)

4. Originally Posted by genius1
i got m= -5/12 am i right?
???

5. Originally Posted by genius1