The circle is (x+3)^2 + (y-5)^2 = 20

How do I justify that (-6,2) is inside?

Printable View

- Sep 16th 2008, 08:04 PMrealintegerzFinding if point is inside or outside of a circle?
The circle is (x+3)^2 + (y-5)^2 = 20

How do I justify that (-6,2) is inside? - Sep 16th 2008, 08:06 PMJhevon
plug in x = -6 and y = 2 and see if you get 20 as the answer... if you do, you are on the circle, if you get mre, you are outside, if you get less, you are inside

you could also use the distance formula to find the distance from the center of your circle to (-6,2). you will then be able to tell if it is inside your circle or not, because you know the radius