
inequalities
2(x3)3(x+2)<5
i seriously don't know where to start. I was thinking of putting 5 on the other side, but i would be stuck from there.
P.S. if i do find the numbers for instance, 3,3, 8. I would have to graph them on a number line and see if its a positive or negative which i know how to do but i am confused on how to figure out the final answer from that

$\displaystyle 2(x3)3(x+2)<5$
1) Distribute
$\displaystyle 2x6 3x6<6$
2) Combine like terms
$\displaystyle x<18$
3) Divide by 1 and remember to change your sign
$\displaystyle x>18$

so there is only 1 answer? in the questions my teacher showed us there were mutiply answers like x^2(x16)(x3)<=0 and the answer was 3<=x<=16
and how you get <6 when it was <5?

The amount of answers depend on the degree of the exponent. So in this case it was to the degree of 1 so you had 1 answer. Now $\displaystyle x^2$ is to the degree of 2 so you will have at most 2 solutions