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Math Help - inverse question help!

  1. #1
    Junior Member
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    inverse question help!

    how do you find the inverse funtion of (3x-2)^2=17 for x≥ 2/3

    i know you are suppose to issolate for x then switch x and y but i did that and didnt get the answer provided with the book.
    their answer was x= √(17)/3 + 2/3

    can someone show me in steps?
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  2. #2
    MHF Contributor
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    You need a function, not an equation, in order to find an inverse. What is the function for which you are being asked to find the inverse?
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  3. #3
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    it just says solve each equations by finding an inverse funtion
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  4. #4
    MHF Contributor
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    All right. Suppose the function is f(x) where f(x) = (3x-2)^2. This is how to find the inverse: Write it as y = (3x-2)^2 and then interchange x and y: x = (3y-2)^2.

    Now take the square root of both sides: \sqrt{x} = 3y - 2

    Add two to both sides: \sqrt{x} + 2 = 3y

    Divide both sides by 3: \frac{\sqrt{x} + 2}{3} = y

    So that is your inverse function.
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