
inverse question help!
how do you find the inverse funtion of (3x2)^2=17 for x≥ 2/3
i know you are suppose to issolate for x then switch x and y but i did that and didnt get the answer provided with the book.
their answer was x= √(17)/3 + 2/3
can someone show me in steps?

You need a function, not an equation, in order to find an inverse. What is the function for which you are being asked to find the inverse?

it just says solve each equations by finding an inverse funtion

All right. Suppose the function is f(x) where $\displaystyle f(x) = (3x2)^2$. This is how to find the inverse: Write it as $\displaystyle y = (3x2)^2$ and then interchange x and y: $\displaystyle x = (3y2)^2$.
Now take the square root of both sides: $\displaystyle \sqrt{x} = 3y  2$
Add two to both sides: $\displaystyle \sqrt{x} + 2 = 3y$
Divide both sides by 3: $\displaystyle \frac{\sqrt{x} + 2}{3} = y$
So that is your inverse function.