Investigate the conic section 4x^2+Y^2-8x+4y+4=0 give all pertinent information and sketch
i have no idea what conics are and what am i supposed to do
Hello,
Conic section - Wikipedia, the free encyclopedia
$\displaystyle 4x^2+y^2-8x+4y+4=0$
$\displaystyle (4x^2-8x+4)+y^2+4y=0$
$\displaystyle 4(x^2-2x+1)+y^2+4y+4-4=0$
$\displaystyle 4(x-1)^2+(y+2)^2=4$
Divide by 4 :
$\displaystyle (x-1)^2+\frac{(y+2)^2}{2^2}=1$
See here : Conic section - Wikipedia, the free encyclopedia the formula of the ellipse