The title pretty much explains the question:
What is the perpendicular distance from the pt 5, 4 to the line y = 1/2x + 6?
If you could please tell the answer and explain how you got there that would be great. thanks
The title pretty much explains the question:
What is the perpendicular distance from the pt 5, 4 to the line y = 1/2x + 6?
If you could please tell the answer and explain how you got there that would be great. thanks
Let's call line : line k.
Find the equation of the line whose slope is the negative reciprocal of line K and it includes the point (5, 4). Call this line J. You will need to use the point-slope form equation:
Find the point of intersection of these 2 lines. The perpendicular distance from the pt 5, 4 to the line is the distance from (5,4) to the point of intersection.
Hello, gobbajeezalus!
There is a formula for this problem, but I'll walk through it for you . . .What is the perpendicular distance from to the line ?
The given line has slope
The line perpendicular to it has slope
has point (5,4) and slope -2
. . Its equation is: .
Where do and intersect?
. .
Hence: . . They intersect at: .
The desired distance is: .
. .