The title pretty much explains the question:

What is the perpendicular distance from the pt 5, 4 to the line y = 1/2x + 6?If you could please tell the answer and explain how you got there that would be great. thanks

- Sep 13th 2008, 06:36 PMgobbajeezalusWhat is the perpendicular distance from the pt 5, 4 to the line y = 1/2x + 6?
The title pretty much explains the question:

*What is the perpendicular distance from the pt 5, 4 to the line y = 1/2x + 6?*If you could please tell the answer and explain how you got there that would be great. thanks

- Sep 13th 2008, 06:56 PMChop Suey
Let's call line : line k.

Find the equation of the line whose slope is the negative reciprocal of line K and it includes the point (5, 4). Call this line J. You will need to use the point-slope form equation:

Find the point of intersection of these 2 lines. The perpendicular distance from the pt 5, 4 to the line is the distance from (5,4) to the point of intersection. - Sep 13th 2008, 07:10 PMSoroban
Hello, gobbajeezalus!

Quote:

What is the perpendicular distance from to the line ?

The given line has slope

The line perpendicular to it has slope

has point (5,4) and slope -2

. . Its equation is: .

Where do and intersect?

. .

Hence: . . They intersect at: .

The desired distance is: .

. .

- Sep 13th 2008, 07:28 PMShyam