Then the initial position of the runner, (100,0), means he is at the point (100,0), . On your drawing , that is at x=100, y=0. Or it is at the x-axis, 100 m from the (0,0).
Then he ran at 4 m/sec counterclockwise for 30 minutes or (30*60) = 1800 seconds.
What is the final position Of Quinn then in coordinates form?
It is easier for me to explain it with computations but you want to do it yourself so....