The equation: H(t)=sqr root(3t+5)

The question: What is the average rate of change of H(t) with respect to t as t changes from 2 to 2.01?

Can anyone explain this to me?

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- Sep 10th 2008, 12:04 PMjemadd2Is anyone familiar with Rate of change?
The equation: H(t)=sqr root(3t+5)

The question: What is the average rate of change of H(t) with respect to t as t changes from 2 to 2.01?

Can anyone explain this to me? - Sep 10th 2008, 12:07 PMMoo
- Sep 10th 2008, 12:14 PMjemadd2
So this means:

f(2.01) - f(2) / 2.01-2 ?

is this correct? - Sep 10th 2008, 12:15 PMMoo
- Sep 10th 2008, 12:21 PMjemadd2
- Sep 10th 2008, 12:24 PMMoo
- Sep 10th 2008, 12:26 PMjemadd2
wow thank you so much....im glad i understand now :)