Plotting Complex Variables on Argand Diagrams

• Aug 8th 2006, 06:38 AM
c00ky
Plotting Complex Variables on Argand Diagrams
Hello again guys,

I have the following problem:

Problem:

a) Plot the following complex variables on an Argand diagram

(i) 2 + j5
(ii) 3 - j6
(iii) - 4 + j10
(iv) - 6 - j3

b) Convert the (i) and (ii) above into their Polar Equivalents, show ALL working.

c) Add (i) and (ii) above and express the result in rectangular form.

d) Subtract (iii) from (ii) above and express the result in rectangular form.

e) Multiply (i) and (iii) above by first converting to Polar form and express the result in Polar form.

f) Divide (iii) by (iv) above by first converting to Polar form and express the result in Polar form.

IT'S PRETTY HARD I KNOW! can anbody help as i'm totally lost.
• Aug 8th 2006, 07:31 AM
ThePerfectHacker
1)Look at diagram below.

2)Look at the first line. Let $\displaystyle \theta$ be the angle is forms. Then $\displaystyle \tan \theta = \frac{5}{2}=2.5$. Thus, $\displaystyle \tan^{-1} (2.5)\approx 1.2$.
The radius of this is, $\displaystyle \sqrt{2^2+5^2}=\sqrt{29}$.
Therefore, expressed in polar form is,
$\displaystyle \sqrt{29}(\cos 1.2+i\sin 1.2)$

Look at the second line. Let $\displaystyle \psi$ be the angle it forms (acute). Then, $\displaystyle \tan \psi =\frac{6}{3}=2$. Thus, $\displaystyle \psi = \tan^{-1}(2)\approx 1.1$. The radius of this is, $\displaystyle \sqrt{3^2+6^2}=\sqrt{45}$. Therefore, expressed in polar form is,
$\displaystyle \sqrt{45}[\cos (-1.1)+i\sin (-1.1)]$
Note the minus because we need it to give a minus in front of sine because the point is below x-axis.
• Aug 8th 2006, 11:04 AM
c00ky
For the polar form of (ii) my answer is:

6.7 (the distance from 0,0)
and the angle as 63.43