You did nothing wrong . . . leep going!
Find the area of the triangle with vertices (0,-3), (4,-4) and (-2,6)
So for this one i found 2 vectors: . . . . . Right!
took the cross product of the two to get: . . . . . Yes!
Where am i going wrong?
Recall that the magnitude of the cross product gives the area of the parallelogram.
Area of parallelogram: .
Therefore, area of triangle: .