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Thank you so much to everyone that is helping me
Find the area of the triangle with vertices http://mathcs.chapman.edu/webwork2_f...984cec8771.png, http://mathcs.chapman.edu/webwork2_f...9e21732301.png, and http://mathcs.chapman.edu/webwork2_f...e424343f71.png
so for this one i found 2 vectors
4i-j+0k
-6i+10j+0k
took the cross product of the two to get 40k - (6k) which equals 34k, so
where am i going wrong?
Hello, Allie!
You did nothing wrong . . . leep going!
Quote:
Find the area of the triangle with vertices (0,-3), (4,-4) and (-2,6)
So for this one i found 2 vectors: .. . . . Right!
took the cross product of the two to get: .. . . . Yes!
Where am i going wrong?
Recall that the magnitude of the cross product gives the area of the parallelogram.
Area of parallelogram: .
Therefore, area of triangle: .
ohh yess i see now thank you so much