just really confused.
list three additional points on a line that has a slope of 3/2 and goes through (3,-1)
Please Help
Thanks
There are a number of ways this can be done...
since the slope is defined as $\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{\text{rise}}{\text{run}}$, and the slope given to us is $\displaystyle m=\frac{3}{2}$, we see that from a given point on the line, we can increase the y value by three and increase the x value by two.
So one additional point could be $\displaystyle (3+3,-1+3)=(6,2)$
Also, note that $\displaystyle \frac{3}{2}=\frac{-3}{-2}$
So we can subtract three from a y value of a point on the line, and subtract 2 from the x value of a point on the line.
So using the original point given to you, we see another possible point could be $\displaystyle (3-3,-1-2)=(0,-3)$
I leave it for you to find another possible point on the line.
I hope this makes sense!
--Chris