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Math Help - yet another log simplification

  1. #1
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    yet another log simplification

    I hope I'm not considered spamming

    anyway

    Solve for x
    eax = Cebx, where a b

    now, what has me dazed is that capital "C". Is it another variable? or is i something special? If not, then why the heck did they capitalize it?

    little things like this irk me.
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  2. #2
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    Did you mean:
    e^{ax} = Ce^{bx}

    Where a, b, and c are different constants?
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  3. #3
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    Quote Originally Posted by Chop Suey View Post
    Did you mean:
    e^{ax} = Ce^{bx}

    Where a, b, and c are different constants?

    yes, thats exactly what I meant. Sorry about the typo.
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  4. #4
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    C is just a "big" constant

    e^{ax} = Ce^{bx}

    \frac{e^{ax}}{e^{bx}} = C

    e^{ax-bx} = C

    e^{x(a-b)} = C

    x(a-b) = \ln{C}

    x = \frac{\ln{C}}{a-b}
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  5. #5
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    ARG I cant stand this online math mumbo jumbo.

    I put in almost that exact answer, but didnt capitalize the C. curses.

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