# Math Help - yet another log simplification

1. ## yet another log simplification

I hope I'm not considered spamming

anyway

Solve for x
eax = Cebx, where a b

now, what has me dazed is that capital "C". Is it another variable? or is i something special? If not, then why the heck did they capitalize it?

little things like this irk me.

2. Did you mean:
$e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?

3. Originally Posted by Chop Suey
Did you mean:
$e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?

yes, thats exactly what I meant. Sorry about the typo.

4. C is just a "big" constant

$e^{ax} = Ce^{bx}$

$\frac{e^{ax}}{e^{bx}} = C$

$e^{ax-bx} = C$

$e^{x(a-b)} = C$

$x(a-b) = \ln{C}$

$x = \frac{\ln{C}}{a-b}$

5. ARG I cant stand this online math mumbo jumbo.

I put in almost that exact answer, but didnt capitalize the C. curses.