# yet another log simplification

• Sep 1st 2008, 12:16 PM
leftyguitarjoe
yet another log simplification
I hope I'm not considered spamming:o

anyway

Solve for x
eax = Cebx, where a http://www.webassign.net/images/neq.gif b

now, what has me dazed is that capital "C". Is it another variable? or is i something special? If not, then why the heck did they capitalize it?

little things like this irk me.(Angry)
• Sep 1st 2008, 12:20 PM
Chop Suey
Did you mean:
$e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?
• Sep 1st 2008, 12:23 PM
leftyguitarjoe
Quote:

Originally Posted by Chop Suey
Did you mean:
$e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?

yes, thats exactly what I meant. Sorry about the typo.
• Sep 1st 2008, 12:28 PM
skeeter
C is just a "big" constant

$e^{ax} = Ce^{bx}$

$\frac{e^{ax}}{e^{bx}} = C$

$e^{ax-bx} = C$

$e^{x(a-b)} = C$

$x(a-b) = \ln{C}$

$x = \frac{\ln{C}}{a-b}$
• Sep 1st 2008, 12:30 PM
leftyguitarjoe
ARG I cant stand this online math mumbo jumbo.

I put in almost that exact answer, but didnt capitalize the C. curses.

http://www.webassign.net/www30/symIm...8c9fcaeb1d.gif