# yet another log simplification

• Sep 1st 2008, 11:16 AM
leftyguitarjoe
yet another log simplification
I hope I'm not considered spamming:o

anyway

Solve for x
eax = Cebx, where a http://www.webassign.net/images/neq.gif b

now, what has me dazed is that capital "C". Is it another variable? or is i something special? If not, then why the heck did they capitalize it?

little things like this irk me.(Angry)
• Sep 1st 2008, 11:20 AM
Chop Suey
Did you mean:
$\displaystyle e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?
• Sep 1st 2008, 11:23 AM
leftyguitarjoe
Quote:

Originally Posted by Chop Suey
Did you mean:
$\displaystyle e^{ax} = Ce^{bx}$

Where a, b, and c are different constants?

yes, thats exactly what I meant. Sorry about the typo.
• Sep 1st 2008, 11:28 AM
skeeter
C is just a "big" constant

$\displaystyle e^{ax} = Ce^{bx}$

$\displaystyle \frac{e^{ax}}{e^{bx}} = C$

$\displaystyle e^{ax-bx} = C$

$\displaystyle e^{x(a-b)} = C$

$\displaystyle x(a-b) = \ln{C}$

$\displaystyle x = \frac{\ln{C}}{a-b}$
• Sep 1st 2008, 11:30 AM
leftyguitarjoe
ARG I cant stand this online math mumbo jumbo.

I put in almost that exact answer, but didnt capitalize the C. curses.

http://www.webassign.net/www30/symIm...8c9fcaeb1d.gif