Express the given quantity as a single logarithm.

and now for my attempt

oh, BTW, sqrt = square root. I dont know how to make the symbol on this forum.

$\displaystyle ln(1+x^6)-ln(cos(x))+(ln(x)/2)$

$\displaystyle ln((1+x^6)/(cos(x))+ln(x)/2$

$\displaystyle ln((1+x^6)/(cos(x))+ln(sqrt(x))$

$\displaystyle ln((1+x^6)/(cos(x)(ln(sqrt(x))$

$\displaystyle ln((sqrt(x)(x^6+1))/cos(x))$

man, I wish I could make this look nicer so its easier to read. But anyway, that last entry is what I got. I just want to be sure.