Solve each trigonometric equation on the interval
0 <or=to x < 2pi....Does this mean to find all the answers between 0 degrees and 360 degrees?
(1) cos^2 (x) - sin^2 (x) + sin (x) = 0
cos^2 (x) = 1 - sin^2 (x)
I replace cos^2 (x) with 1 - sin^2 (x) in the equation, right?
I get this:
1 - sin^2 (x) - sin^2 (x) + sin (x) = 0
Do I factor out sin(x)? If so, what happens next to get me on the right track to the answer? OR....do I rearrange the sin(x) terms to be in the form ax^2 + bx + c?
(2) sin(4x) - sin(6x) = 0
I know there is a sin(2x) but I have never seen a 4x or 6x applied to a trig function.
Does sin(4x) = sin(2x) + sin(2x)?
Does sin(6x) = sin(3x) + sin(3x)?
If so, where do I go from there?