Three lines have the equations 2x+3y-4=0
3x-y-17=0
x-3y-10=0
Show wether these lines are cocurrent or not.
Anyone know how to do this, darn im rubbish at maths
Hello, mattymaths!
Given three lines: .$\displaystyle \begin{array}{cccc}2x+3y-4&=&0 &{\color{blue}[1]}\\ 3x-y-17&=&0 & {\color{blue}[2]}\\ x-3y-10&=&0 &{\color{blue}[3]}\end{array}$
Show whether these lines are concurrent or not.
"Concurrent" means they intersect at one point.
Find the intersection of [1] and [3].
Find the intersection of [2] and [3].
Are they the same point?
I thought that, but i just cant seem to get it right, can you see where im going wrong?
[1] 2x + 3y = 4
[2] 3x -y = 17 X3
[1] 2x + 3y=4
[2] 9x - 3y=51
11x=55?
doesnt seem to work out right, i'm not too sure what ive done wrong
SORRY I'VE NOTICED MY INCREDIBLY SILLY MISTAKE!
Anyway i done 2(5)+3y=4
so 10+3y=4
3y=4-10
3y=-6
y=-2
so (5,-2) is this right? i hope so ha!
Thank you very much for the replies btw