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Math Help - ACT Stuff

  1. #1
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    Post ACT Stuff

    Which of the following points lies on the perimeter of the circle given by the equation (x-2)squared+ (y+5)squared = 16?
    A. (2,-5)
    B. (2,-1)
    C. (-2,5)
    D. (-2,1)
    E. (square root of 2, square root of 5)

    How do i even go about finding out the options? -confuzzled-
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  2. #2
    o_O
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    (x-2)^2 + (y+5)^2 = 16

    Each of the options are coordinates of the form (x, y). So simply plug in the values of each coordinate pair to determine whether or not the above equation is satisfied. For example, looking at A. (2, -5), we have:
    (2 -2)^2 + ((-5)+5)^2 = 0 + 0 = 0 \neq 16

    So A cannot be the right answer.
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  3. #3
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    Quote Originally Posted by o_O View Post
    (x-2)^2 + (y+5)^2 = 16

    Each of the options are coordinates of the form (x, y). So simply plug in the values of each coordinate pair to determine whether or not the above equation is satisfied. For example, looking at A. (2, -5), we have:
    (2 -2)^2 + ((-5)+5)^2 = 0 + 0 = 0 \neq 16

    So A cannot be the right answer.
    Your awesome. And i am ashamed of how stupid i felt after you explained that :x
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