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Thread: ACT Stuff

  1. #1
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    Post ACT Stuff

    Which of the following points lies on the perimeter of the circle given by the equation (x-2)squared+ (y+5)squared = 16?
    A. (2,-5)
    B. (2,-1)
    C. (-2,5)
    D. (-2,1)
    E. (square root of 2, square root of 5)

    How do i even go about finding out the options? -confuzzled-
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  2. #2
    o_O
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    $\displaystyle (x-2)^2 + (y+5)^2 = 16$

    Each of the options are coordinates of the form $\displaystyle (x, y)$. So simply plug in the values of each coordinate pair to determine whether or not the above equation is satisfied. For example, looking at A. (2, -5), we have:
    $\displaystyle (2 -2)^2 + ((-5)+5)^2 = 0 + 0 = 0 \neq 16$

    So A cannot be the right answer.
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  3. #3
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    Quote Originally Posted by o_O View Post
    $\displaystyle (x-2)^2 + (y+5)^2 = 16$

    Each of the options are coordinates of the form $\displaystyle (x, y)$. So simply plug in the values of each coordinate pair to determine whether or not the above equation is satisfied. For example, looking at A. (2, -5), we have:
    $\displaystyle (2 -2)^2 + ((-5)+5)^2 = 0 + 0 = 0 \neq 16$

    So A cannot be the right answer.
    Your awesome. And i am ashamed of how stupid i felt after you explained that :x
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