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Math Help - Express the function...

  1. #1
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    Express the function...

    Express the function in the form f g. (Use only elementary functions, but not the identity function, g(x) = x.)


    I am totally lost on what to do.

    When it gives mt F(x) and tells me to find g(x) I can do fine... but this.... this is weird.




    AND this one confounds me as well
    Express the function in the form f g. (Use only elementary functions, but not the identity function, g(x) = x.)
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by leftyguitarjoe View Post
    Express the function in the form f g. (Use only elementary functions, but not the identity function, g(x) = x.)


    I am totally lost on what to do.

    Then it gives mt F(x) and tells me to find g(x) I can do fine... but this.... this is weird.
    my first question may seem silly to you, but consider it seriously: do you understand what f \circ g means.

    i do not like problems like this, because you usually have several answers that are correct. but i bet this is the answer they are looking for:

    f(x) = \sqrt[3]{x} and g(x) = \frac x{4 + x}

    now see if you can tell why that answer makes sense, after considering the question i asked you earlier

    AND this one confounds me as well
    Express the function in the form f compose g. (Use only elementary functions, but not the identity function, g(x) = x.)
    if you think you got it, try this one yourself and tell us your answer
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  3. #3
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    Yes, I am familiar with f(g)) and such.

    Thanks for the help. I'll go work out the other one and report back.
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  4. #4
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    ok, so the other one should be:

    f(x) =

    and

    g(x) =

    EDIT
    err I mean to make those "t"'s not "x"'s

    but ya catch my drift.
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  5. #5
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by leftyguitarjoe View Post
    ok, so the other one should be:

    f(x) =

    and

    g(x) =
    yup
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  6. #6
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    gah.


    I think too hard. thats my problem haha.
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  7. #7
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by leftyguitarjoe View Post
    gah.


    I think too hard. thats my problem haha.
    that's a lot of people's problem

    good luck
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