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Math Help - Limit Problem

  1. #1
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    Limit Problem

    Lim t^3+t^2-5t-3/t^3-3t+2
    x->1

    Please help, can't seem to factor the top portion at all.
    Last edited by Sturm88; August 28th 2008 at 09:35 PM.
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  2. #2
    Super Member 11rdc11's Avatar
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    You don't need too, just plug in 2 for (t)

    It equals -1/4
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  3. #3
    Super Member 11rdc11's Avatar
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    This is what it looks like right?

    \frac{t^3+t^2-5t-3}{t^3-3t+2}
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  4. #4
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    Hey sorry x approaches 1 instead of 2
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  5. #5
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    Quote Originally Posted by Sturm88 View Post
    Hey sorry x approaches 1 instead of 2
    Then the limit is equal to -oo.
    Note that the denominator is (x-1)^2(x+2) which is always positive for x > -2 and note that numerator is always negative for x > 0 ......
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  6. #6
    Senior Member nikhil's Avatar
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    hi Sturm88
    conventional method for finding limit can also be used.(though its lengthy but simple and general)
    put t=1+h and find limit at h->0+ this will give you right hand limit
    put t=1-h and find limit at h->0+ this will give you left hand limit
    when you will calculate them you will get limit=- infinity
    that is
    left hand limit=right hand limit=-infinity
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