Divide the following: [x^3 - a^3]/(x - a) Is the numerator the difference of two perfect cubes? If so, how do I divide this fraction? The different variables confused me.
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Do you know the difference of cubes: $\displaystyle a^{3} - b^{3} = (a-b)(a^2+ab+b^2)$ If you factor the numerator according to the above formula, you should see a common factor that'll cancel.
Originally Posted by o_O Do you know the difference of cubes: $\displaystyle a^{3} - b^{3} = (a-b)(a^2+ab+b^2)$ If you factor the numerator according to the above formula, you should see a common factor that'll cancel. Yes, I know the difference of cubes. I finally got the answer x^2 + xa + a^2 with no remainder. Thanks
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