Divide the following:

[x^3 - a^3]/(x - a)

Is the numerator the difference of two perfect cubes?

If so, how do I divide this fraction?

The different variables confused me.

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- Aug 26th 2008, 09:05 PMmagentaritaPolynomial Division
Divide the following:

[x^3 - a^3]/(x - a)

Is the numerator the difference of two perfect cubes?

If so, how do I divide this fraction?

The different variables confused me. - Aug 26th 2008, 09:14 PMo_O
Do you know the difference of cubes: $\displaystyle a^{3} - b^{3} = (a-b)(a^2+ab+b^2)$

If you factor the numerator according to the above formula, you should see a common factor that'll cancel. - Aug 27th 2008, 08:20 AMmagentaritayes...