# Polynomial Division

• August 26th 2008, 09:05 PM
magentarita
Polynomial Division
Divide the following:

[x^3 - a^3]/(x - a)

Is the numerator the difference of two perfect cubes?

If so, how do I divide this fraction?

The different variables confused me.
• August 26th 2008, 09:14 PM
o_O
Do you know the difference of cubes: $a^{3} - b^{3} = (a-b)(a^2+ab+b^2)$

If you factor the numerator according to the above formula, you should see a common factor that'll cancel.
• August 27th 2008, 08:20 AM
magentarita
yes...
Quote:

Originally Posted by o_O
Do you know the difference of cubes: $a^{3} - b^{3} = (a-b)(a^2+ab+b^2)$

If you factor the numerator according to the above formula, you should see a common factor that'll cancel.

Yes, I know the difference of cubes.
I finally got the answer x^2 + xa + a^2 with no remainder.

Thanks