1. ## logarithms

Find the logarithm using the change of base formula.

the change of bas forumla is $logb^m = loga^m/(loga^b)$

here the thing we use to log using the CoB formula.

log5^19

2. Originally Posted by mcdanielnc89
Find the logarithm using the change of base formula.

the change of bas forumla is ${\color{red}\log_b m = \frac{\log_a m}{\log_a b}}$

here the thing we use to log using the CoB formula.

log5^19 Do you mean: ${\color{red}\log_5 19}$? Change it to what base?
Change of base formula modified in red.

$\log_5 19=\frac{\log_{10} 19}{\log_{10} 5}=\frac{\ln 19}{\ln 5}$

3. Originally Posted by masters
Change of base formula modified in red.

$\log_5 19=\frac{\log_{10} 19}{\log_{10} 5}=\frac{\ln 19}{\ln 5}$
yes thats wha rti mean.. Change it to bas ten i'm guessing. i hnestly have no clue.

a=10. thats all i know if thats what ur meaning.

4. not sure what u mean i guess.

5. I see all kinds of people looking, yet no oen seems to respond.. erm,

6. Originally Posted by mcdanielnc89
I see all kinds of people looking, yet no oen seems to respond.. erm,
masters already responded. there is nothing left to say. all that remains now is for you to plug what he wrote into your calculator and compute it. you can use either the log on your calculator or the ln, he gave you the formula for both