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Math Help - logarithms

  1. #1
    Junior Member mcdanielnc89's Avatar
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    logarithms

    Find the logarithm using the change of base formula.


    the change of bas forumla is logb^m = loga^m/(loga^b)


    here the thing we use to log using the CoB formula.


    log5^19
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  2. #2
    A riddle wrapped in an enigma
    masters's Avatar
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    Quote Originally Posted by mcdanielnc89 View Post
    Find the logarithm using the change of base formula.


    the change of bas forumla is {\color{red}\log_b m = \frac{\log_a m}{\log_a b}}


    here the thing we use to log using the CoB formula.


    log5^19 Do you mean: {\color{red}\log_5 19}? Change it to what base?
    Change of base formula modified in red.

    \log_5 19=\frac{\log_{10} 19}{\log_{10} 5}=\frac{\ln 19}{\ln 5}
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  3. #3
    Junior Member mcdanielnc89's Avatar
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    Quote Originally Posted by masters View Post
    Change of base formula modified in red.

    \log_5 19=\frac{\log_{10} 19}{\log_{10} 5}=\frac{\ln 19}{\ln 5}
    yes thats wha rti mean.. Change it to bas ten i'm guessing. i hnestly have no clue.



    a=10. thats all i know if thats what ur meaning.
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  4. #4
    Junior Member mcdanielnc89's Avatar
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    not sure what u mean i guess.
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  5. #5
    Junior Member mcdanielnc89's Avatar
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    Question

    I see all kinds of people looking, yet no oen seems to respond.. erm,
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mcdanielnc89 View Post
    I see all kinds of people looking, yet no oen seems to respond.. erm,
    masters already responded. there is nothing left to say. all that remains now is for you to plug what he wrote into your calculator and compute it. you can use either the log on your calculator or the ln, he gave you the formula for both
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