Solve for x: (15x+4)^1/2=4-(2x+3)^1/2 Thank you!
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Originally Posted by ss103 Solve for x: (15x+4)^1/2=4-(2x+3)^1/2 Thank you! start by squaring both sides $\displaystyle 15x + 4 = 16 - 8 \sqrt{2x + 3} + 2x + 3$ so we have $\displaystyle 13x - 15 = 8 \sqrt{2x + 3}$ now what?
how did you get the second half of the equation? (on the other side of the equal sign)
Originally Posted by ss103 how did you get the second half of the equation? (on the other side of the equal sign) I was off by a sign. it should be $\displaystyle 15 - 13x = 8 \sqrt{2x + 3}$ all i did was solve the equation for $\displaystyle 8 \sqrt{2x + 3}$ by moving everything else over the equal sign
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