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Math Help - Precalc

  1. #1
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    Precalc

    Solve for x:
    (15x+4)^1/2=4-(2x+3)^1/2

    Thank you!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ss103 View Post
    Solve for x:
    (15x+4)^1/2=4-(2x+3)^1/2

    Thank you!
    start by squaring both sides

    15x + 4 = 16 - 8 \sqrt{2x + 3} + 2x + 3

    so we have 13x - 15 = 8 \sqrt{2x + 3}

    now what?
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  3. #3
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    how did you get the second half of the equation?
    (on the other side of the equal sign)
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ss103 View Post
    how did you get the second half of the equation?
    (on the other side of the equal sign)
    I was off by a sign. it should be 15 - 13x = 8 \sqrt{2x + 3}

    all i did was solve the equation for 8 \sqrt{2x + 3} by moving everything else over the equal sign
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