Establish the identity.

[sin^3 (x) + cos^3 (x)]/[1 - 2 cos^2 (x)] =

[sec(x) - sin(x)]/[tan(x) - 1]

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- Aug 24th 2008, 02:56 PMmagentaritaEstablish the Identity
Establish the identity.

[sin^3 (x) + cos^3 (x)]/[1 - 2 cos^2 (x)] =

[sec(x) - sin(x)]/[tan(x) - 1]

- Aug 24th 2008, 03:32 PMJhevon
- Aug 24th 2008, 03:43 PMskeeter
actually, this is not an identity ... the equation is not true for odd multiples of

- Aug 24th 2008, 04:00 PMSoroban
Hello, magentarita!

Quote:

Establish the identity: .

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Divide top and bottom by

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- Aug 25th 2008, 02:53 AMmagentaritaThanks...
I thank you all, especially Jhevon and Soroban.

- Aug 25th 2008, 07:21 AMJhevon
skeeter had a valid point as well. the secant is undefined for the specified values of x. so that may cause problems. after graphing the two functions, i saw that the graphs were the same and so i overlooked it. i guess the point here was to do the algebraic manipulation to show you know your trig identities and how to use them

- Aug 25th 2008, 08:54 PMmagentaritaNo doubt...