Find the domain and range for each quadratic function.
a. y = x^2 – 6x +5
b. y = 3x^2 + 2x +9
The RHS of both of these are defined for all of , soOriginally Posted by pashah
their domains are both the set of all real numbers.
Because these both represent parabolas which go to as
goes to , they can take all values greater than teir minimums.
The minimum of the first occurs when , which is at
, where , so for a. the range is .
The minimum of the second occurs when , which is at
, where , so for a. the range is .
RonL
I do this slight diffrently.Originally Posted by pashah
Rewrite as,
Now, you need to find all such as this quadradic equation has a real solution. That happens when, the discrimanant is non-negative.
Simplify,
Thus,
Thus,
Proceede the same,b. y = 3x^2 + 2x +9
Work with discrimanant,