the equation is h=-0.4 d^2 + 2d.

h=height above water, d=horizontal distance.

Q1) how high above the water is the dolphin when it has travelled 2 m horizontally from its starting point?

A1) h=-0.4 (2)^2 + (2)

h=-1.6 + 2

h=0.4m

(im fairly sure that this is correct)

Q2) what horizontal distance does the dolphin cover when it first reaches a height of 25cm?

A2) 0.25=-0.4 d^2 + 2

0.25 + 0.4 = d^2 + d

0.65=d^2 +2

square root of 0.65=d + d

0.81= d+d

0.81/2=d

0.405m =d

Q3) what horizontal distance does the dolphin cover when it next reaches a height of 25cm? explain.

A3) i am unsure of this answer

Q4)what horizontal distance does the dolphin cover in one leap? (hint:what is the value of h when the dolphin has completed the leap?)

A4) i am unsure of this answer

Q5) can this dolphin reach a height of:

a)0.5 m

b)1 during a leap?

How can you work this out without actually solving the equation?

A5) i am unsure of this answer

Q6) find the greatest height that the dolphin reaches during its leap.

A6) i am unsure of this answer

CAN YOU PLEASE HELP ME WITH THIS INVESTIGATION!!!!!!!!!I NEED YOUR HELP SOON!!!!!!!!!!!!