the equation is h=-0.4 d^2 + 2d.
h=height above water, d=horizontal distance.
Q1) how high above the water is the dolphin when it has travelled 2 m horizontally from its starting point?
A1) h=-0.4 (2)^2 + (2)
h=-1.6 + 2
(im fairly sure that this is correct)
Q2) what horizontal distance does the dolphin cover when it first reaches a height of 25cm?
A2) 0.25=-0.4 d^2 + 2
0.25 + 0.4 = d^2 + d
square root of 0.65=d + d
Q3) what horizontal distance does the dolphin cover when it next reaches a height of 25cm? explain.
A3) i am unsure of this answer
Q4)what horizontal distance does the dolphin cover in one leap? (hint:what is the value of h when the dolphin has completed the leap?)
A4) i am unsure of this answer
Q5) can this dolphin reach a height of:
b)1 during a leap?
How can you work this out without actually solving the equation?
A5) i am unsure of this answer
Q6) find the greatest height that the dolphin reaches during its leap.
A6) i am unsure of this answer
CAN YOU PLEASE HELP ME WITH THIS INVESTIGATION!!!!!!!!!I NEED YOUR HELP SOON!!!!!!!!!!!!
The dolphin enters/leaves the water when , so you need to find so that:
which may be factorised to give:
so the dolphin leaves the water when and re-enters the whater when