# Limit of ln(x+1) as x->infinity

• Aug 13th 2008, 11:18 PM
JOhkonut
Limit of ln(x+1) as x->infinity
Hi, I'm a bit rusty on my math since it is summer...
but i have to do this summer assignment.

The original question is which of the following functions has a horizontal asymptote at y=-1? and it lists like 5 equations, one which is y=ln(x+1)

I'm thinking that you have to find the limit as x->infinity and negative infinity, and if the answer is -1, that is my equation. If that's wrong, point it out please.

And no graphing calculator, and i really don't want to hand draw these graphs (i have to show work)

Thanks!
• Aug 13th 2008, 11:24 PM
CaptainBlack
Quote:

Originally Posted by JOhkonut
Hi, I'm a bit rusty on my math since it is summer...
but i have to do this summer assignment.

The original question is which of the following functions has a horizontal asymptote at y=-1? and it lists like 5 equations, one which is y=ln(x+1)

I'm thinking that you have to find the limit as x->infinity and negative infinity, and if the answer is -1, that is my equation. If that's wrong, point it out please.

And no graphing calculator, and i really don't want to hand draw these graphs (i have to show work)

Thanks!

$\lim_{x \to \infty} \ln(x+1) = \infty$

and $\ln(x+1)$ is undefined in the reals for $x\le -1$

RonL
• Aug 13th 2008, 11:30 PM
CaptainBlack
Quote:

Originally Posted by JOhkonut
Hi, I'm a bit rusty on my math since it is summer...
but i have to do this summer assignment.

The original question is which of the following functions has a horizontal asymptote at y=-1? and it lists like 5 equations, one which is y=ln(x+1)

I'm thinking that you have to find the limit as x->infinity and negative infinity, and if the answer is -1, that is my equation. If that's wrong, point it out please.

And no graphing calculator, and i really don't want to hand draw these graphs (i have to show work)

Thanks!

You don't need a calculator, there are many options if you have access to a computer. There should be a built in calculator with the operating system, or (not many people know this) just type the calculation into Google and Google calculator will give the answer. Not to mention the myriad of online function/graph plotters that you will find if you google for online graph plotter, the first hit is here.

RonL
• Aug 14th 2008, 09:19 AM
JOhkonut
Quote:

Originally Posted by CaptainBlack
You don't need a calculator, there are many options if you have access to a computer. There should be a built in calculator with the operating system, or (not many people know this) just type the calculation into Google and Google calculator will give the answer. Not to mention the myriad of online function/graph plotters that you will find if you google for online graph plotter, the first hit is here.

RonL

Actually, it's not that I don't have a graphing calculator, I'm just not allowed to use one for that problem. Do you think that just writing that the limit goes to infinity is sufficient?
• Aug 14th 2008, 10:14 AM
CaptainBlack
Quote:

Originally Posted by JOhkonut
Actually, it's not that I don't have a graphing calculator, I'm just not allowed to use one for that problem. Do you think that just writing that the limit goes to infinity is sufficient?

It depends on what you are supposed to know. If you know that $\ln(x)$ increases without bound as $x$ goes to infinity you need just say so.
RonL
• Aug 14th 2008, 10:18 AM
JOhkonut
Quote:

Originally Posted by CaptainBlack
It depends on what you are supposed to know. If you know that $\ln(x)$ increases without bound as $x$ goes to infinity you need just say so.
RonL

If it's mathematical common sense, then yes, i think I'm supposed to know that.
• Aug 14th 2008, 12:40 PM
colby2152
Quote:

Originally Posted by JOhkonut
Actually, it's not that I don't have a graphing calculator, I'm just not allowed to use one for that problem. Do you think that just writing that the limit goes to infinity is sufficient?

This depends on your teacher, but I would assume that it is efficient enough. One thing you can is rewrite the limit equation to prove your point even further.

$\lim_{x \rightarrow \infty} ln(x)$

$\lim_{e^x \rightarrow \infty} e^{ln(x)}$

In order for $a^x$ to go to infinity, the base must be positive and x must have a limit of infinity. Both of those work for this limit, so the following can be said:

$\lim_{x \rightarrow \infty} x$