Write the expression below as a single logarithm. 3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x) NOTE: log_5 means "log base 5."
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Originally Posted by magentarita Write the expression below as a single logarithm. 3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x) NOTE: log_5 means "log base 5." $\displaystyle = \log_5 (3x + 1)^3 - \log_5 (2x - 1)^2 - \log_5 (x)$ $\displaystyle = \log_5 (3x + 1)^3 - \left[ \log_5 (2x - 1)^2 + \log_5 (x) \right]$ $\displaystyle = \log_5 (3x + 1)^3 - \log_5 \left( (2x-1)^2 x \right)$ $\displaystyle = \, ....$
Is the last expression the answer?
Originally Posted by magentarita Is the last expression the answer? Is the last expression in the form of a single logarithm? Now you have to use the log rule $\displaystyle \log A - \log B = \log \frac{A}{B}$ to get an expression in the form of a single logarithm ....
That's what I thought.
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