One More Single Log

**magentarita** · August 7th 2008, 02:45 AM

Write the expression below as a single logarithm.

3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x)

NOTE: log_5 means "log base 5."

**mr fantastic** · August 7th 2008, 03:26 AM

Originally Posted by magentarita

Write the expression below as a single logarithm.

3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x)

NOTE: log_5 means "log base 5."

$= \log_5 (3x + 1)^3 - \log_5 (2x - 1)^2 - \log_5 (x)$

$= \log_5 (3x + 1)^3 - \left[ \log_5 (2x - 1)^2 + \log_5 (x) \right]$

$= \log_5 (3x + 1)^3 - \log_5 \left( (2x-1)^2 x \right)$

$= \, ....$

**magentarita** · August 7th 2008, 07:32 PM

Is the last expression the answer?

**mr fantastic** · August 7th 2008, 08:38 PM

Originally Posted by magentarita

Is the last expression the answer?

Is the last expression in the form of a single logarithm?

Now you have to use the log rule $\log A - \log B = \log \frac{A}{B}$ to get an expression in the form of a single logarithm ....

**magentarita** · August 8th 2008, 06:49 AM

That's what I thought.

Thread: One More Single Log

LinkBack

Thread Tools

Display

One More Single Log

Then...

ok...

Similar Math Help Forum Discussions

Single Vectors

Single equation, single unknown. How to solve?

single solution?

single fraction

Write As Single Log

Search Tags