# Math Help - One More Single Log

1. ## One More Single Log

Write the expression below as a single logarithm.

3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x)

NOTE: log_5 means "log base 5."

2. Originally Posted by magentarita
Write the expression below as a single logarithm.

3 log_5 (3x + 1) - 2 log_5(2x - 1) - log_5 (x)

NOTE: log_5 means "log base 5."
$= \log_5 (3x + 1)^3 - \log_5 (2x - 1)^2 - \log_5 (x)$

$= \log_5 (3x + 1)^3 - \left[ \log_5 (2x - 1)^2 + \log_5 (x) \right]$

$= \log_5 (3x + 1)^3 - \log_5 \left( (2x-1)^2 x \right)$

$= \, ....$

3. ## Then...

Is the last expression the answer?

4. Originally Posted by magentarita
Is the last expression the answer?
Is the last expression in the form of a single logarithm?

Now you have to use the log rule $\log A - \log B = \log \frac{A}{B}$ to get an expression in the form of a single logarithm ....

5. ## ok...

That's what I thought.