This one really stumped me =[ Does anyone know how to verify it?
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Originally Posted by Kitty216 This one really stumped me =[ Does anyone know how to verify it? I think the (alpha)/3 distracts you. You're used to dealing up to (alpha)/2 only for angles. Since the alpha/3 is uniform throughout, then let's say angle alpha/ 3 = angle B. Then the original equation/identity will be sinBcosB = (1/2)sin(2B) ....which is easy.
Using
Wow.. replacing the alpha/3 with a B really helps! So at the end do I just replace the all the B's back with the alpha/3?
Originally Posted by Kitty216 Wow.. replacing the alpha/3 with a B really helps! So at the end do I just replace the all the B's back with the alpha/3? Yes. Later on, in your future Math subjects, you will see that substitutions like that are common.
Thanks for the help! =DD
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