Write Log In Terms of a and b

**magentarita** · August 4th 2008, 03:32 AM

Suppose that ln 2 = a and in 3 = b. Use rules of logarithms to write each log in terms of a and b.

(1) ln (2/3)

(2) ln (4throot{(2/3)}

**Chop Suey** · August 4th 2008, 03:35 AM

$\ln{(a \cdot b)} = \ln{a} + \ln{b}$

$\ln{\left(\frac{a}{b}\right)} = \ln{a} - \ln{b}$

$\ln{(a)^n} = n\ln{a}$

$\sqrt[n]{a} = a^{\frac{1}{n}}$

**mr fantastic** · August 4th 2008, 04:07 AM

Originally Posted by Chop Suey

$\ln{(a \cdot b)} = \ln{a} + \ln{b}$

$\ln{\left(\frac{a}{b}\right)} = \ln{a} - \ln{b}$

$\ln{(a)^n} = n\ln{a}$

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Since the pronumerals a and b are used in the question, your excellent advice might be misunderstood. Re-pronumeraling:

$\ln{(A \cdot B)} = \ln{A} + \ln{B}$

$\ln{\left(\frac{A}{B}\right)} = \ln{A} - \ln{B}$

$\ln{(A)^n} = n\ln{A}$

$\sqrt[n]{A} = A^{\frac{1}{n}}$

**magentarita** · August 4th 2008, 06:20 AM

I thank both of you.

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