http://i146.photobucket.com/albums/r.../relation2.jpg

It would be great if someone can help me solve this!

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- August 3rd 2008, 02:54 AMKitty216another relation problem
http://i146.photobucket.com/albums/r.../relation2.jpg

It would be great if someone can help me solve this! - August 3rd 2008, 02:12 PMMoo
- August 3rd 2008, 03:02 PMKitty216
yay!! I also got those =] Do you know how to find the domain and range of these functions? This is all new to me heh.

- August 6th 2008, 03:30 PMMoo
Sorry for the delay :)

For the domain, just remember that you can't divide something by 0, so x for which the denominator is = 0 may not be in the domain ! That's nearly all you need here.

In other cases, you may need to know that, for example, you can't have a negative number under a square root.

For the range, you may need this information : -1 <= cos(x) (or sin(x)) <= 1