Find a so that the graph of f(x) = log_a (x) contains the point (1/2, -4). NOTE: log_a (x) = "log sub a x"
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Originally Posted by magentarita Find a so that the graph of f(x) = log_a (x) contains the point (1/2, -4). NOTE: log_a (x) = "log sub a x" (1/2,-4) will satisfy the equation -4=log_a (1/2) a^-4=1/2 a^4=2 therfor a=+2^(1/4) as a can not be <0
Originally Posted by magentarita Find a so that the graph of f(x) = log_a (x) contains the point (1/2, -4). NOTE: log_a (x) = "log sub a x" Let The general rule to simplify this is:
Last edited by Simplicity; Aug 1st 2008 at 04:33 AM. Reason: Latex correction and to avoid confusion
I thank both of you, especially Air for his use of LATEX.
Originally Posted by magentarita I thank both of you, especially Air for his use of LATEX. You fell for the old gender bias trap ...... I believe that s/he is XX not XY ....
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