b) passes through the point R(-6, 2) and S(4, -2)
First, we need a vector, v that will be parallel to the line. We thus let v be the vector that starts at point S and ends at point R.
v = <-6-4, 2-(-2)> = <-10, 4>.
Now that we have our direction vector v, all we need to do is choose of our two given points, R or S. Let's use R.
The equation of our line r = <-6, 2> + t<-10, 4> = <-6-10t, 2+4t>.
In parametric form:
In symmetric form: