b) passes through the point R(-6, 2) and S(4, -2)

First, we need a vector,vthat will be parallel to the line. We thus letvbe the vector that starts at point S and ends at point R.

v= <-6-4, 2-(-2)> = <-10, 4>.

Now that we have our direction vectorv, all we need to do is choose of our two given points, R or S. Let's use R.

The equation of our liner= <-6, 2> + t<-10, 4> = <-6-10t, 2+4t>.

In parametric form:

In symmetric form:

.