Gravity

• Jul 26th 2008, 07:55 AM
magentarita
Gravity
In physics, it is established that the acceleration due to gravity, g, (in meters/sec^2), at a height h meters above the sea level is given by the function

g(h) = [3.99 x 10^(14)]/[6.374 x 10^6 + h]^2, where 6.374 x 10^6 is the radius of Earth (in meters).

(a) What is the acceleration due to gravity at seal level?

(b) The Sears Tower in Chicago, Ill, is 443 meters tall. What is the acceleration due to gravity at the top of the Sears Tower?

• Jul 26th 2008, 09:49 AM
Chris L T521
Quote:

Originally Posted by magentarita
In physics, it is established that the acceleration due to gravity, g, (in meters/sec^2), at a height h meters above the sea level is given by the function

g(h) = [3.99 x 10^(14)]/[6.374 x 10^6 + h]^2, where 6.374 x 10^6 is the radius of Earth (in meters).

(a) What is the acceleration due to gravity at seal level?

(b) The Sears Tower in Chicago, Ill, is 443 meters tall. What is the acceleration due to gravity at the top of the Sears Tower?

At sea level, h = 0.

Thus,

http://img.photobucket.com/albums/v4...5e2143a3-4.jpg

The Sears tower is 443 meters tall. Thus, h = 443.

Therefore,

http://img.photobucket.com/albums/v4...5e2143a3-5.jpg

Does this make sense?

--Chris
• Jul 26th 2008, 03:46 PM
magentarita
It makes sense...