In physics, it is established that the acceleration due to gravity, g, (in meters/sec^2), at a height h meters above the sea level is given by the function
g(h) = [3.99 x 10^(14)]/[6.374 x 10^6 + h]^2, where 6.374 x 10^6 is the radius of Earth (in meters).
(a) What is the acceleration due to gravity at seal level?
(b) The Sears Tower in Chicago, Ill, is 443 meters tall. What is the acceleration due to gravity at the top of the Sears Tower?
Originally Posted by magentarita
At sea level, h = 0.
The Sears tower is 443 meters tall. Thus, h = 443.
Does this make sense?
It makes sense...
Your reply makes perfect sense.