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Math Help - Please HELP!!! Math problem is so tricky!!

  1. #1
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    Please HELP!!! Math problem is so tricky!!

    This is the math problem:

    An Ellipse whose equation is ((x^2/4a^2) + (y^2/b^2) = 1)

    And a hyperbola whose equation is (x^2/a^2) - (y^2/b^2) = 1

    Are drawn on the same axis. If one of the points of intersection is ((6/5*square root of 10),(3/5* square root of 15), find each equation.
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  2. #2
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    If y^2 / b^2 = 1 - x^2 / (4a^2)

    Then (x^2/a^2) - (1 - x^2 / (4a^2)) = 1

    This leads to x^2 = (8/5)a^2

    Similarly, one can determine that y^2 = (3/5)b^2

    From the given points, we have x^2 = 72/5 and y^2 = 27/5

    That seem to be enough to find a and b.

    Let's see what you get.
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