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Math Help - I need help

  1. #1
    Junior Member
    Joined
    Jul 2008
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    47

    I need help

    For each equation that has a graph, identify the type of graph. It may be necessary to transform the equation.

    x=3ysquare+5y-6
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  2. #2
    Member
    Joined
    Jul 2008
    Posts
    78
    The equation of a parabola with a vertical axis of symmetry (ie a parabola that opens up or down) is y = ax^2 + bx + c.

    But lets go back to the original equation,
    x = 3y^2 + 5y - 6

    Notice that instead of having y = ax^2 + bx + c, we have a parabola in the form of x = ay^2 + ay + c. This is a parabola with a horizontal axis of symmetry (ie a parabola that opens left or right).

    It may help to make a table of x and y values and plug in random numbers to make a rough sketch of the graph.
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