I have a question I'm stuck on:
Find two functions such that f(x)= f-1(x). (For all x in domain of f)
It's not f minus 1. I don't know how to type the Value of Inverse of f at x.
An assistance would be greatly appreciated!
Question 1 a. of this thread is relevant: http://www.mathhelpforum.com/math-he...questions.html
See if you can place conditions on a, b, c and d so that the function $\displaystyle y = \frac{ax+b}{cx+d}$ is its own inverse.
Well, for the second one, f(x) = -x, find the inverse function.
Let y = f(x) = -x.
Now, switch the roles of y and x:
$\displaystyle x = -y$
Now solve for y:
$\displaystyle y = -x$.
This is your inverse function. So
$\displaystyle f^{-1}(x) = -x = f(x)$
You do the one for y = x.
-Dan