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Math Help - Graphing Functions

  1. #1
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    Graphing Functions

    I have a question I'm stuck on:

    Find two functions such that f(x)= f-1(x). (For all x in domain of f)

    It's not f minus 1. I don't know how to type the Value of Inverse of f at x.

    An assistance would be greatly appreciated!







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  2. #2
    Moo
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    Huu hello !

    What about y=x and y=-x ?
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  3. #3
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    Quote Originally Posted by Maga22 View Post
    I have a question I'm stuck on:

    Find two functions such that f(x)= f-1(x). (For all x in domain of f)

    It's not f minus 1. I don't know how to type the Value of Inverse of f at x.

    An assistance would be greatly appreciated!
    Question 1 a. of this thread is relevant: http://www.mathhelpforum.com/math-he...questions.html

    See if you can place conditions on a, b, c and d so that the function y = \frac{ax+b}{cx+d} is its own inverse.
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  4. #4
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    Quote Originally Posted by Moo View Post
    Huu hello !

    What about y=x and y=-x ?
    Thanks. So it seemed easy. These are two functions such that f(x) = the value of inverse of f at x?
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  5. #5
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    Quote Originally Posted by Maga22 View Post
    Thanks. So it seemed easy. These are two functions such that f(x) = the value of inverse of f at x?
    Well, for the second one, f(x) = -x, find the inverse function.

    Let y = f(x) = -x.

    Now, switch the roles of y and x:
    x = -y

    Now solve for y:
    y = -x.

    This is your inverse function. So
    f^{-1}(x) = -x = f(x)

    You do the one for y = x.

    -Dan
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