The minimum value of z=4x+10y subject to

3x+y<=to24

6x+4y<=to66

x>=to0,y>=to 0. is.

My answer after looking at a list of possible answers is 32, is this right.

a.165

b.110

c.44

d.32

Thanks for any help given.

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- Jul 28th 2006, 01:01 AM #1

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- Jul 28th 2006, 04:13 AM #2

- Jul 28th 2006, 02:07 PM #3

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- Jul 28th 2006, 03:01 PM #4

- Jul 28th 2006, 03:13 PM #5
Soroban, I just ran this through the Linear Programming solver in Maple and it gave me (0,0) as the minimum. I looked right past the origin.

Looks like the list of answers is omitting the correct minimum. That's why you're the man and I'm just a dogface .

Good 'ketch' .

- Jul 29th 2006, 01:20 AM #6

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- Jul 29th 2006, 05:18 PM #7

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- Jul 29th 2006, 05:36 PM #8

- Jul 29th 2006, 06:04 PM #9

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- Jul 29th 2006, 07:19 PM #10Originally Posted by
**kwtolley***minimum*value is 0, not on the list. So there is a typo. From this linear programming solver, which you can use to both solve the problem or check your work, the*maximum*value is 165, answer a.

If you have linear programming problems to solve in the future, you may want to bookmark that solver.

- Jul 30th 2006, 01:50 AM #11