The minimum value of z=4x+10y subject to

3x+y<=to24

6x+4y<=to66

x>=to0,y>=to 0. is.

My answer after looking at a list of possible answers is 32, is this right.

a.165

b.110

c.44

d.32

Thanks for any help given.

Results 1 to 11 of 11

- July 28th 2006, 02:01 AM #1

- Joined
- Jun 2006
- Posts
- 165

- July 28th 2006, 05:13 AM #2

- July 28th 2006, 03:07 PM #3

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 11,903
- Thanks
- 764

- July 28th 2006, 04:01 PM #4

- July 28th 2006, 04:13 PM #5
Soroban, I just ran this through the Linear Programming solver in Maple and it gave me (0,0) as the minimum. I looked right past the origin.

Looks like the list of answers is omitting the correct minimum. That's why you're the man and I'm just a dogface .

Good 'ketch' .

- July 29th 2006, 02:20 AM #6

- Joined
- Jun 2006
- Posts
- 165

- July 29th 2006, 06:18 PM #7

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 10

- July 29th 2006, 06:36 PM #8

- July 29th 2006, 07:04 PM #9

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 10

- July 29th 2006, 08:19 PM #10Originally Posted by
**kwtolley***minimum*value is 0, not on the list. So there is a typo. From this linear programming solver, which you can use to both solve the problem or check your work, the*maximum*value is 165, answer a.

If you have linear programming problems to solve in the future, you may want to bookmark that solver.

- July 30th 2006, 02:50 AM #11