exponential

**norwoodjay** · July 12th 2008, 09:19 AM

Dissolving a chemical; The amount of a chemical that will dissolve in asolution increases exponentially as the (Celsius) temperature t is increased according to the model:
A(t)=10e .0095t

At what temperature will 5 g dissolve?

**CaptainBlack** · July 12th 2008, 09:36 AM

Originally Posted by norwoodjay

Dissolving a chemical; The amount of a chemical that will dissolve in asolution increases exponentially as the (Celsius) temperature t is increased according to the model:
A(t)=10e .0095t

At what temperature will 5 g dissolve?

This requires that you solve the equaltion:

$5=10e^{0.0095t}$

or:

$1=2e^{0.0095t}$

you do this by first taking natural logs to get:

$\ln(1)=\ln(2)+0.0095t$

Now solve this linear equation

RonL

**norwoodjay** · July 12th 2008, 08:58 PM

I need the final answer I am kind of confused.

**topsquark** · July 13th 2008, 04:25 AM

Originally Posted by norwoodjay

I need the final answer I am kind of confused.

What, specifically, do you need help on? CaptainBlack's derivation or solving the equation from the point where he left off?

-Dan

**norwoodjay** · July 13th 2008, 07:32 AM

Yes were you left off from.

**janvdl** · July 13th 2008, 10:07 AM

Originally Posted by norwoodjay

Yes were you left off from.

Originally Posted by CaptainBlack

This requires that you solve the equaltion:

$5=10e^{0.0095t}$

or:

$1=2e^{0.0095t}$

you do this by first taking natural logs to get:

$\ln(1)=\ln(2)+0.0095t$

Now solve this linear equation

RonL