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Math Help - exponential

  1. #1
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    exponential

    Dissolving a chemical; The amount of a chemical that will dissolve in asolution increases exponentially as the (Celsius) temperature t is increased according to the model:
    A(t)=10e .0095t


    At what temperature will 5 g dissolve?
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by norwoodjay View Post
    Dissolving a chemical; The amount of a chemical that will dissolve in asolution increases exponentially as the (Celsius) temperature t is increased according to the model:
    A(t)=10e .0095t


    At what temperature will 5 g dissolve?
    This requires that you solve the equaltion:

    5=10e^{0.0095t}

    or:

    1=2e^{0.0095t}

    you do this by first taking natural logs to get:

    \ln(1)=\ln(2)+0.0095t

    Now solve this linear equation

    RonL
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  3. #3
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    answer

    I need the final answer I am kind of confused.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by norwoodjay View Post
    I need the final answer I am kind of confused.
    What, specifically, do you need help on? CaptainBlack's derivation or solving the equation from the point where he left off?

    -Dan
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  5. #5
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    Yes were you left off from.
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  6. #6
    Bar0n janvdl's Avatar
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    Quote Originally Posted by norwoodjay View Post
    Yes were you left off from.
    Quote Originally Posted by CaptainBlack View Post
    This requires that you solve the equaltion:

    5=10e^{0.0095t}

    or:

    1=2e^{0.0095t}

    you do this by first taking natural logs to get:

    \ln(1)=\ln(2)+0.0095t

    Now solve this linear equation

    RonL

    \ln(1) = 0

    \ln(2) = 0.693147

    So we have:

    0.0095t = -0.693147

    t = \frac{-0.693147}{0.0095}
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